Chemical Equilibrium Chemical Equilibrium – Ch. 6 Chemical Equilibrium – Ch. 6 Chemical Equilibrium – Ch. 6 Chemical Equilibrium – Ch. 6

Chemical Equilibrium Chemical Equilibrium – Ch. 6 Chemical Equilibrium – Ch. 6 Chemical Equilibrium – Ch. 6 Chemical Equilibrium – Ch. 6 www.phwiki.com

Chemical Equilibrium Chemical Equilibrium – Ch. 6 Chemical Equilibrium – Ch. 6 Chemical Equilibrium – Ch. 6 Chemical Equilibrium – Ch. 6

Nodar, John, Meteorologist has reference to this Academic Journal, PHwiki organized this Journal Chemical EquilibriumChapter 6E-mail: benzene4president@gmail.comWeb-site: http://clas.sa.ucsb.edu/staff/terri/Chemical Equilibrium – Ch. 61. Consider the following reaction: N2 (g) + 3 H2 (g) 2 NH3 (g) a. Write the equilibrium expression (K in addition to Kp) b. What is the value of Kp at 25°C if the equilibrium pressures as long as N2, H2 in addition to NH3 were 1.8 atm, 0.5 atm in addition to 0.017 atm respectively. c. What is the value of K at 25°C Kp = K(RT)n d. Does the reaction favor reactants or productsChemical Equilibrium – Ch. 6Where does the equilibrium lieK > 1 The products are favoredK < 1 The reactants are favored European Management Center Paris FR www.phwiki.com

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Chemical Equilibrium – Ch. 6Chemical Equilibrium – Ch. 62. Which reaction does the K = Kp a. P4 (s) + 6 Cl2 (g) 4 PCl3 (g) b. H2O (l) H2O (g) c. H2 (g) + Cl2 (g) 2 HCl (g) d. C3H8 (g) + 5 O2 (g) 3 CO2 (g) + 4 H2O (g)Kp = K(RT)nChemical Equilibrium – Ch. 63. Given the following in as long as mation: H2(g) + I2(g) 2 HI(g) K = 54.0 N2(g) + 3 H2(g) 2 NH3(g) K = 96.0 Determine the value of the equilibrium constant as long as the following reaction: 2 NH3(g) + 3 I2(g) 6 HI(g) + N2(g)

Chemical Equilibrium – Ch. 6Chemical Equilibrium – Ch. 64. Consider the following reaction: UO2 (s) + 4HF (g) UF4 (g) + 2H2O (g) Kp = 11 If you fill a 5 L container with 15 g of UO2, 1.1 atm of HF, 0.75 atm of UF4 in addition to 5.9 atm of H2O, what will be the mass of the solid UO2 at equilibrium a. 15 g b. > 15 g c. < 15 g d. not enough in as long as mationChemical Equilibrium – Ch. 6 Chemical Equilibrium – Ch. 65. Consider the following reaction: N2 (g) + O2 (g) 2 NO (g) Kp = Initially the partial pressures of N2 in addition to O2 are 1 atm in addition to 3 atm respectively. At equilibrium the pressure of NO is 1.5 atm. What is the Kp as long as this reactionChemical Equilibrium – Ch. 66. Pure PCl5 is introduced into an empty rigid 5-L flask at 24 °C with a pressure of 0.45 atm. The PCl5 is heated to 90 °C upon which it decomposes into solid P in addition to gaseous Cl2. 2 PCl5 (g) 2 P (s) + 5 Cl2 (g) At equilibrium the total pressure is measured to be 0.93 atm. What is the equilibrium constant (Kp) at 90 °C What percentage of the PCl5 decomposed How many grams of P are in the flask at equilibriumChemical Equilibrium – Ch. 67. At a certain temperature the partial pressures of an equilibrium mixture of N2O4 (g) in addition to NO2 (g) are 0.34 atm in addition to 1.2 atm respectively. N2O4 (g) 2 NO2 (g) The volume of the container is doubled. Find the new partial pressures when the equilibrium is re-established. Chemical Equilibrium – Ch. 68. Consider the following reaction: 2 NOBr (g) 2 NO (g) + Br2 (g) Kp = 34 An unknown pressure of NOBr is put into a rigid container at 40 °C, equilibrium is reached when 86 % of the original partial pressure of NOBr has decomposed. What was the initial pressure of the NOBr What is the total pressure in the flask at equilibriumChemical Equilibrium – Ch. 69. At a particular temperature Kp = 5.7x10-8 as long as the following reaction: 2 C (s) + 3 H2 (g) C2H6 (g) What is the pressure of C2H6 at equilibrium if initially there's 5 g of C in addition to 3 atm of H2 Chemical Equilibrium – Ch. 610. Consider the following endothermic reaction at equilibrium: CCl4 (g) C (s) + 2 Cl2 (g)a. Is heat absorbed or released as the reaction goes as long as wardb. Which way will the reaction shift if the temperature is increasedc. What happens to K as the temperature is increasedd. Which way will the reaction shift if the partial pressure of CCl4 is increasede. Which way will the reaction shift if you add more Cf. Which way will the reaction shift if you remove Cl2g. Which way will the reaction shift if you compress the systemh. Which way will the reaction shift if you add a catalyst Answer Key – Ch. 6You have completed ch. 6Answer Key – Ch. 6Answer Key – Ch. 61. continued d. Does the reaction favor reactants or products Since Kp < 1 in addition to /or K < 1 the reaction favors the reactants2. Which reaction does the K = Kp a. P4 (s) + 6Cl2 (g) 4PCl3 (g) b. H2O (l) H2O (g) c. H2 (g) + Cl2 (g) 2HCl (g) d. C3H8 (g) + 5O2 (g) 3CO2 (g) + 4H2O (g)If n=0 Kp=K n=0 when there are the same number of molesof gaseous reactants as gaseous products 3. Given the following in as long as mation: H2(g) + I2(g) 2 HI(g) K = 54.0 N2(g) + 3 H2(g) 2 NH3(g) K = 96.0 Determine the value of the equilibrium constant as long as the following reaction: 2 NH3(g) + 3 I2(g) 6 HI(g) + N2(g)Answer Key – Ch. 6Rxn 2FlippedRxn 1x 3Rxn 1x 3Rxn 2Flipped3 H2(g) + 3 I2(g) 6 HI(g) K = 54.032 NH3(g) N2(g) + 3 H2(g) K = 96.0-12 NH3(g) + 3 I2(g) 6 HI(g) + N2(g) K = (54.03)(96.0-1) = 1640Answer Key – Ch. 6Since K < Q the reaction will go backwards thereby increasing the mass of the UO2Answer Key – Ch. 65. Consider the following reaction: N2 (g) + O2 (g) 2 NO (g) Kp = Initially the partial pressures of N2 in addition to O2 are 1 atm in addition to 3 atm respectively. At equilibrium the pressure of NO is 1.5 atm. What is the Kp as long as this reaction Answer Key – Ch. 66. Pure PCl5 is introduced into an empty rigid flask at 24 °C with a pressure of 0.45 atm. The PCl5 is heated to 90 °C upon which it decomposes into solid P in addition to gaseous Cl2. 2 PCl5 (g) 2 P (s) + 5 Cl2 (g) At equilibrium the total pressure is measured to be 0.93 atm. What is the equilibrium constant (Kp) at 90 °C What percentage of the PCl5 decomposedContinue to next slide Answer Key – Ch. 6Answer Key – Ch. 6 continue to next slide Nodar, John WKRG-TV Meteorologist www.phwiki.com

Answer Key – Ch. 67. continuedPN2O4 = 0.12 atmPNO2 = 0.71 atmAnswer Key – Ch. 68. Consider the following reaction: 2 NOBr (g) 2 NO (g) + Br2 (g) Kp = 34 An unknown pressure of NOBr is put into a rigid container at 40 °C, equilibrium is reached when 86 % of the original partial pressure of NOBr has decomposed. What was the initial pressure of the NOBr What is the total pressure in the flask at equilibrium continue to next slideAnswer Key – Ch. 6

Answer Key – Ch. 69. At a particular temperature Kp = 5.7×10-8 as long as the following reaction: 2 C (s) + 3 H2 (g) C2H6 (g) What is the pressure of C2H6 at equilibrium if initially there’s 5 g of C in addition to 3 atm of H2 Negligible b/c Kp is so small10. Consider the following endothermic reaction at equilibrium: CCl4 (g) C (s) + 2 Cl2 (g)a. Is heat absorbed or released as the reaction goes as long as ward Since the reaction is endothermic heat is absorbed if the reaction goes as long as ward in addition to vice versab. Which way will the reaction shift if the temperature is increased As the temperature is increased the system will have more heat causing the reaction to shift rightc. What happens to K as the temperature is increased As the temperature is increased heat is being added causing the reaction to shift right producing more products thereby causing an increase in Kd. Which way will the reaction shift if the partial pressure of CCl4 is increased More reactant pushes the reaction to the right continue to next slideAnswer Key – Ch. 6e. Which way will the reaction shift if you add more C Adding more solid will have no effect on the equilibriumf. Which way will the reaction shift if you remove Cl2 Removing a product causes the reaction to shift to the rightg. Which way will the reaction shift if you compress the system Decreasing the volume of the system causes the reaction to shift to the side with fewer moles of gas – in this case the lefth. Which way will the reaction shift if you add a catalyst Catalysts will speed up the as long as ward in addition to reverse direction there as long as e having no effect on the equilibriumAnswer Key – Ch. 6

Answer Key – Ch. 6

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