# Normal Force Normal Force Warning!!!! F NET F

## Normal Force Normal Force Warning!!!! F NET F

Radin, Robin, Executive Producer has reference to this Academic Journal, PHwiki organized this Journal Normal ForceNormal ForceNormal as long as ce is a as long as ce that exists due to contact between two surfaces.Normal as long as ce is always directed perpendicular to the surface.(The Normal is any line perpendicular to a surface. We use it to assign a direction to a surface).The magnitude of Normal Force on an object will change to suit a particular situation ( in addition to keep Fnet=ma valid).Warning!!!! FNET FNReaction ForceSometimes FN is called the Reaction Force(R). In the case on the right, the box is pushed into the wall, consequently, the box pushes the wall. If the box pushes the wall, (according to Newton 3) then the wall must push back on the box there as long as e FN is the reaction to the box pushing the wall.

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Normal ForcePerpendicular to a surfaceYou push a box into the wall (to the left). The normal as long as ce on the box is to the right, away from the wall.A box sits on a slope, the normal as long as ce on the box is diagonally up in addition to to the right, perpendicular to the slope.A box sits on a horizontal surface, the normal as long as ce on the box is directed upwards, perpendicular to the surface.Normal ForceIt changes depending on the situationThe magnitude of Normal Force on an object will change to suit a particular situation.Consider the following situations of the same box.You push a 6.0 kg box against a wall with 120 N of as long as ce (dont ask me why, you are the one doing it!).Since you apply 120 N of as long as ce, since the box does not accelerate into the wall, the wall must be pushing back on the box with 120 N of as long as ce.If you increase how hard you push to 180 N, Normal as long as ce will also increase to 180 N.2. Now the box is just sitting on the floor.It is not accelerating, so the net as long as ce on the box is 0.N.Up as long as ce must be equal to down as long as ce.Fg=FNFg=mg=6.0×9.8Fg=58.8 N= 59N.Since the net as long as ce is 0, the magnitude of the normal as long as ce must also be 59 N.