# Sample 2 lenses Goal: To understand multiple lens systems.

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## Sample 2 lenses Goal: To understand multiple lens systems.

Bethany College West Virginia, US has reference to this Academic Journal, Goal: To understand multiple lens systems. Objectives: To understand how so that calculate values in consideration of 2 lens combos To understand the human eye 2 lenses We have learned how so that do the equations in consideration of the first lens, but what happens when you have 2 lenses? The image from the first lens becomes the object in consideration of the second lens. The separation distance between lenses is denoted as s. Everything is normal after that. So, 1/p2 + 1/q2 = 1/f2 And p2 = s ? q1 The final image type is determined by the 2nd lens. Sample Lets make sure we still know the lesson from yesterday? You have 2 lenses. We will do the 2nd lens in the 2nd sample. An object is 10 cm from lens one. The focal length is 3 cm. What is the image distance (i.e. q1)?

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Sample 2 1/p2 + 1/q2 = 1/f2 And p2 = s ? q1 For the previous question, if the separation distance between lenses is 20 cm then what is p2? Sample 3 Now that we have p2 as 15.7 cm, if the focal length in consideration of the 2nd lens is 10 cm then what is the image distance in consideration of the 2nd lens? Magnification Each lens will have a magnification. How do you think this will work alongside 2 lenses? A) M = M1 + M2 B) M = M1 ? M2 C) M = M1 * M2 D) M = M1 / M2

Sample We will put all this together? We have 2 lenses. An object is placed 6 cm from the first lens. The focal length of the first lens is 2 cm. The 2nd lens is 7 cm from the first lens. The focal length of the 2nd lens is 3 cm. What is the total magnification of the system (to find this you will have so that find q1, q2, M1, in addition to M2)? HW wrinkles Remember that a diverging lens has a negative value in consideration of the focal length. For the projector question, you are supposed so that know that the object is upside down (so the initial height is negative). Sometimes they give you measurements between either object so that image or in the multi lens they ask in consideration of the magnitude of distance from the FIRST lens in addition to not the 2nd. Just be on the lookout in consideration of this trip ups. The Eye Okay time in consideration of some cool stuff in addition to some concepts.

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But what happens? If the eye is not correctly shaped? Myopia (nearsightedness) ? you can focus on nearby objects but not distant ones. This is because the eye?s lens forms the image just in front of the retina. You compensate in consideration of this by using a divergent lens. Can you start fires alongside a lens like this? Hyperopia This is farsightedness. This time you have exactly the opposite problem. The lens doesn?t bend the light enough so the focus is just beyond the retina. To fix this you use a convergent lens. Note you COULD start a fire alongside this kind of lens! Presbyopia At some point a person?s eyes can loose flexibility. You start so that have trouble focusing on nearby objects. While you are not better at seeing far away ones as you would be alongside farsightedness, so that read something near by you need reading glasses. The reading glasses would be similar so that the glasses used in consideration of farsightedness.

The math There is some math in consideration of using glasses. There are two values so that worry about ? the near point in addition to the far point. The near point is the nearest you can clearly see something. The far point is the farthest you can clearly see something. Refractive power P is the refractive power of a lens. P = 1 / f in addition to is in units of Diopters (D). D has units of 1/meters Note that P also = 1/q + 1/p And if you have multiple lenses close together: P = P1 + P2 + ? The equations? P = 1 / f = 1/q + 1/p However q in addition to p are now something a bit different. You have 2 limits so that your vision ? new point in addition to far point. For one of those two you find the original value in addition to the new value. The original value is q in addition to is negative (you will be making a virtual image). The new value is p. Be sure that you choose either far points or near points in consideration of both, don?t mix in addition to match.