Springs & Strings Springs Hooke’s Law Springs Hooke’s Law Springs Tension

Springs & Strings Springs Hooke’s Law Springs Hooke’s Law Springs Tension www.phwiki.com

Springs & Strings Springs Hooke’s Law Springs Hooke’s Law Springs Tension

Stapleton, Jean, Faculty Advisor has reference to this Academic Journal, PHwiki organized this Journal Springs & Strings Springs Spring Force A stretched or compressed spring exerts one of the most common contact as long as ces. A spring can either push (when compressed) or pull (when stretched). In either case, the tail of the vector as long as ce is attached to the contact point. There is no special symbol as long as the spring as long as ce, but we can use Fsp. Hooke’s law as long as springs states that the as long as ce increases linearly with the amount the spring is stretched or compressed: k spring constant units N/m Hooke’s Law Springs

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Hooke’s law as long as springs states that the as long as ce increases linearly with the amount the spring is stretched or compressed. The as long as ce is negative because it always opposes the compression or extension of the spring. Hooke’s Law Springs 27 IP The equilibrium length of a certain spring with a as long as ce constant of k = 250 N/m is 0.18 m. (a) What as long as ce is required to stretch this spring to twice its equilibrium length (b) Is the as long as ce required to compress the spring to half its length the same as in part (a) Explain. 0.18 m F = -k x x = 0.18 m F = -(250 N/m)(0.18 m) F = -45 N (a) (b) x = – 0.09 m F = -(250 N/m)(- 0.09 m) F = 22.5 N The tension transmitted by a string, rope, cable, etc. is the as long as ce exerted by the string at either end in addition to along its length. Tension

The tension in a real rope will vary along its length, due to the weight of the rope. We will assume that all ropes, strings, wires, etc. are massless. So T1 = T2 = T3 Tension Tension ACT What is the reading in N on each the two spring scales shown above 9.8 N Ideal pulleys simply change the direction of the tension. There is no friction in the pulley in addition to the pulleys are massless. Pulleys & Tension

When as long as ces are exerted on connected objects, their accelerations are the same. In the situation below, if we know the as long as ce in addition to the masses, we can find the acceleration in addition to the tension Tension – Connected Objects In addition to the motion of the entire system, we can treat each box as a separate system. Use the entire system to find the acceleration in addition to then use one of the boxes to find the tension. If there is a pulley, it is easiest to have the coordinate system follow the string. Tension – Connected Objects 42. Two buckets of s in addition to hang from opposite ends of a rope that passes over a pulley. One bucket is full in addition to weighs 110 N; the other is only partly filled in addition to weighs 63 N. (a) Initially, you hold onto the lighter bucket to keep it from moving. What is the tension in the rope (b) You release the bucket in addition to the heavier one descends. What is the tension in the rope now (c) Eventually the heavier bucket l in addition to s in addition to the two buckets come to rest. What is the tension in the rope now (a) Tension will be 110 N (b) Examine entire system.

Now examine one of the individual masses. 110 N bucket: The other mass could have been analyzed in order to reach the same value. (c) 63 N in translational equilibrium, the acceleration is 0 (the velocity is constant Translational Equilibrium Tension ACT 2 a. A b. B c. Both tensions are the same In which situation is the tension on the rope larger A B

Equilibrium Tension A 90 kg mountain climber is suspended from ropes as shown. Rope 3 can sustain a maximum tension of 1500 N be as long as e breaking. What is the smallest that angle q can become be as long as e the rope breaks Equilibrium Tension

Stapleton, Jean Campus News Faculty Advisor www.phwiki.com

Stapleton, Jean Faculty Advisor

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